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	<title>Comments on: Number Puzzle #7</title>
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	<link>http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/</link>
	<description>Ramblings of a Christian Mathematician and Bioinformaticist</description>
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		<title>By: tpc</title>
		<link>http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/comment-page-1/#comment-128376</link>
		<dc:creator>tpc</dc:creator>
		<pubDate>Sun, 01 Mar 2009 00:48:14 +0000</pubDate>
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		<description>Dave, 

As far as I remember, I don&#039;t think there are other answers, for example 9900 is neither divisible by 8 nor 7, so we didn&#039;t need to discard that based on Mr Jones&#039; age, although that would be much faster.</description>
		<content:encoded><![CDATA[<p>Dave, </p>
<p>As far as I remember, I don&#8217;t think there are other answers, for example 9900 is neither divisible by 8 nor 7, so we didn&#8217;t need to discard that based on Mr Jones&#8217; age, although that would be much faster.</p>
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		<title>By: Dave</title>
		<link>http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/comment-page-1/#comment-128094</link>
		<dc:creator>Dave</dc:creator>
		<pubDate>Thu, 26 Feb 2009 15:53:06 +0000</pubDate>
		<guid isPermaLink="false">http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/#comment-128094</guid>
		<description>Oops - didn&#039;t realize that the answer was already posted.</description>
		<content:encoded><![CDATA[<p>Oops &#8211; didn&#8217;t realize that the answer was already posted.</p>
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		<title>By: Dave</title>
		<link>http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/comment-page-1/#comment-128093</link>
		<dc:creator>Dave</dc:creator>
		<pubDate>Thu, 26 Feb 2009 15:50:12 +0000</pubDate>
		<guid isPermaLink="false">http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/#comment-128093</guid>
		<description>Cute puzzle!  However, tpc, the answer is not unique if you don&#039;t have the fact that the last two digits equal the age of Mr. Jones.  I guess a follow up question would be &quot;What other answer(s) would be possible without that constraint?&quot;</description>
		<content:encoded><![CDATA[<p>Cute puzzle!  However, tpc, the answer is not unique if you don&#8217;t have the fact that the last two digits equal the age of Mr. Jones.  I guess a follow up question would be &#8220;What other answer(s) would be possible without that constraint?&#8221;</p>
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		<title>By: Natural Blogarithms &#187; Blog Archive &#187; Number Puzzle #7 &#8211; A solution</title>
		<link>http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/comment-page-1/#comment-127807</link>
		<dc:creator>Natural Blogarithms &#187; Blog Archive &#187; Number Puzzle #7 &#8211; A solution</dc:creator>
		<pubDate>Sun, 22 Feb 2009 21:34:46 +0000</pubDate>
		<guid isPermaLink="false">http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/#comment-127807</guid>
		<description>[...] was the puzzle posted last week: Mr. Jones has eight children of different ages.&#160; On a family trip his oldest child, who is 9, [...]</description>
		<content:encoded><![CDATA[<p>[...] was the puzzle posted last week: Mr. Jones has eight children of different ages.&#160; On a family trip his oldest child, who is 9, [...]</p>
]]></content:encoded>
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		<title>By: tpc</title>
		<link>http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/comment-page-1/#comment-127741</link>
		<dc:creator>tpc</dc:creator>
		<pubDate>Sun, 22 Feb 2009 05:02:35 +0000</pubDate>
		<guid isPermaLink="false">http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/#comment-127741</guid>
		<description>Nice! I managed to solve the problem without using the fact that the last two digits equal the age of Mr Jones, but that involved looking through many cases. I searched and found a much faster solution using that clue.</description>
		<content:encoded><![CDATA[<p>Nice! I managed to solve the problem without using the fact that the last two digits equal the age of Mr Jones, but that involved looking through many cases. I searched and found a much faster solution using that clue.</p>
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		<title>By: Math Teachers at Play #1 &#171; Let&#8217;s Play Math!</title>
		<link>http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/comment-page-1/#comment-127573</link>
		<dc:creator>Math Teachers at Play #1 &#171; Let&#8217;s Play Math!</dc:creator>
		<pubDate>Fri, 20 Feb 2009 12:23:59 +0000</pubDate>
		<guid isPermaLink="false">http://blog.drscottfranklin.net/2009/02/09/number-puzzle-7/#comment-127573</guid>
		<description>[...] Scott Franklin has been sharing stumpers over at Natural Blogarithms. His Number Puzzle #7 is a divisibility challenge from the 2006 AMC [...]</description>
		<content:encoded><![CDATA[<p>[...] Scott Franklin has been sharing stumpers over at Natural Blogarithms. His Number Puzzle #7 is a divisibility challenge from the 2006 AMC [...]</p>
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