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	<title>Comments on: Number Puzzle #6 &#8211; Solution</title>
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	<link>http://blog.drscottfranklin.net/2009/02/06/number-puzzle-6-solution/</link>
	<description>Ramblings of a Christian Mathematician and Bioinformaticist</description>
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		<title>By: Phil H</title>
		<link>http://blog.drscottfranklin.net/2009/02/06/number-puzzle-6-solution/comment-page-1/#comment-142378</link>
		<dc:creator>Phil H</dc:creator>
		<pubDate>Tue, 21 Jul 2009 11:55:01 +0000</pubDate>
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		<description><![CDATA[1 and 8 must go on the central 2 points, as they are the only values with 6 non-neighbours. 

2 must go top/bottom away from 1 as all other remaining nodes are connected to 1, and the same works for 7 (the numbers are symmetric about 4&#124;5).

3 and 6 now similarly have only one position available each, leaving 4 and 5.

So the answer is no, there are no further arrangements.]]></description>
		<content:encoded><![CDATA[<p>1 and 8 must go on the central 2 points, as they are the only values with 6 non-neighbours. </p>
<p>2 must go top/bottom away from 1 as all other remaining nodes are connected to 1, and the same works for 7 (the numbers are symmetric about 4|5).</p>
<p>3 and 6 now similarly have only one position available each, leaving 4 and 5.</p>
<p>So the answer is no, there are no further arrangements.</p>
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